加勒比久久综合,国产精品伦一区二区,66精品视频在线观看,一区二区电影

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

CS439編程代寫、代做Java程序語言
CS439編程代寫、代做Java程序語言

時間:2024-10-13  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



CS439: Introduction to Data Science Fall 2024 
 
Problem Set 1 
 
Due: 11:59pm Friday, October 11, 2024 
 
Late Policy: The homework is due on 10/11 (Friday) at 11:59pm. We will release the solutions 
of the homework on Canvas on 10/16 (Wednesday) 11:59pm. If your homework is submitted to 
Canvas before 10/11 11:59pm, there will no late penalty. If you submit to Canvas after 10/11 
11:59pm and before 10/16 11:59pm (i.e., before we release the solution), your score will be 
penalized by 0.9k
, where k is the number of days of late submission. For example, if you 
submitted on 10/14, and your original score is 80, then your final score will be 80*0.93
=58.** 
for 14-11=3 days of late submission. If you submit to Canvas after 10/16 11:59pm (i.e., after we 
release the solution), then you will earn no score for the homework.  
 
General Instructions 
 
Submission instructions: These questions require thought but do not require long answers. 
Please be as concise as possible. You should submit your answers as a writeup in PDF format, 
for those questions that require coding, write your code for a question in a single source code 
file, and name the file as the question number (e.g., question_1.java or question_1.py), finally, 
put your PDF answer file and all the code files in a folder named as your Name and NetID (i.e., 
Firstname-Lastname-NetID.pdf), compress the folder as a zip file (e.g., Firstname-LastnameNetID.zip),
and submit the zip file via Canvas. 
 
For the answer writeup PDF file, we have provided both a word template and a latex template 
for you, after you finished the writing, save the file as a PDF file, and submit both the original 
file (word or latex) and the PDF file. 
 
Questions 
 
1. Map-Reduce (35 pts) 
 
Write a MapReduce program in Hadoop that implements a simple “People You Might Know” 
social network friendship recommendation algorithm. The key idea is that if two people have a 
lot of mutual friends, then the system should recommend that they connect with each other. 
 
Input: Use the provided input file hw1q1.zip. 
 
The input file contains the adjacency list and has multiple lines in the following format: 
<User><TAB><Friends> 
 Here, <User> is a unique integer ID corresponding to a unique user and <Friends> is a commaseparated
 list of unique IDs corresponding to the friends of the user with the unique ID <User>. 
Note that the friendships are mutual (i.e., edges are undirected): if A is friend with B, then B is 
also friend with A. The data provided is consistent with that rule as there is an explicit entry for 
each side of each edge. 
 
Algorithm: Let us use a simple algorithm such that, for each user U, the algorithm recommends 
N = 10 users who are not already friends with U, but have the largest number of mutual friends 
in common with U. 
 
Output: The output should contain one line per user in the following format: 
 
<User><TAB><Recommendations> 
 
where <User> is a unique ID corresponding to a user and <Recommendations> is a commaseparated
 list of unique IDs corresponding to the algorithm’s recommendation of people that 
<User> might know, ordered by decreasing number of mutual friends. Even if a user has 
fewer than 10 second-degree friends, output all of them in decreasing order of the number of 
mutual friends. If a user has no friends, you can provide an empty list of recommendations. If 
there are multiple users with the same number of mutual friends, ties are broken by ordering 
them in a numerically ascending order of their user IDs. 
 
Also, please provide a description of how you are going to use MapReduce jobs to solve this 
problem. We only need a very high-level description of your strategy to tackle this problem. 
 
Note: It is possible to solve this question with a single MapReduce job. But if your solution 
requires multiple MapReduce jobs, then that is fine too. 
 
What to submit: 
 
(i) The source code as a single source code file named as the question number (e.g., 
question_1.java). 
 
(ii) Include in your writeup a short paragraph describing your algorithm to tackle this problem. 
 
(iii) Include in your writeup the recommendations for the users with following user IDs: 
924, 8941, 8942, **19, **20, **21, **22, 99**, 9992, 9993. 
 
 
2. Association Rules (35 pts) 
 
Association Rules are frequently used for Market Basket Analysis (MBA) by retailers to 
understand the purchase behavior of their customers. This information can be then used for many different purposes such as cross-selling and up-selling of products, sales promotions, 
loyalty programs, store design, discount plans and many others. 
 
Evaluation of item sets: Once you have found the frequent itemsets of a dataset, you need to 
choose a subset of them as your recommendations. Commonly used metrics for measuring 
significance and interest for selecting rules for recommendations are: 
 
2a. Confidence (denoted as conf(A → B)): Confidence is defined as the probability of 
occurrence of B in the basket if the basket already contains A: 
 
conf(A → B) = Pr(B|A), 
 
where Pr(B|A) is the conditional probability of finding item set B given that item set A is 
present. 
 
2b. Lift (denoted as lift(A → B)): Lift measures how much more “A and B occur together” than 
“what would be expected if A and B were statistically independent”: 
* and N is the total number of transactions (baskets). 
 
3. Conviction (denoted as conv(A→B)): it compares the “probability that A appears without B if 
they were independent” with the “actual frequency of the appearance of A without B”: 
 
(a) [5 pts] 
 
A drawback of using confidence is that it ignores Pr(B). Why is this a drawback? Explain why lift 
and conviction do not suffer from this drawback? 
 
(b) [5 pts] 
 
A measure is symmetrical if measure(A → B) = measure(B → A). Which of the measures 
presented here are symmetrical? For each measure, please provide either a proof that the 
measure is symmetrical, or a counterexample that shows the measure is not symmetrical. 
 
(c) [5 pts] 
 A measure is desirable if its value is maximal for rules that hold 100% of the time (such rules are 
called perfect implications). This makes it easy to identify the best rules. Which of the above 
measures have this property? Explain why. 
 
 
Product Recommendations: The action or practice of selling additional products or services to 
existing customers is called cross-selling. Giving product recommendation is one of the 
examples of cross-selling that are frequently used by online retailers. One simple method to 
give product recommendations is to recommend products that are frequently browsed 
together by the customers. 
 
Suppose we want to recommend new products to the customer based on the products they 
have already browsed on the online website. Write a program using the A-priori algorithm to 
find products which are frequently browsed together. Fix the support to s = 100 (i.e. product 
pairs need to occur together at least 100 times to be considered frequent) and find itemsets of 
size 2 and 3. 
 
Use the provided browsing behavior dataset browsing.txt. Each line represents a browsing 
session of a customer. On each line, each string of 8 characters represents the id of an item 
browsed during that session. The items are separated by spaces. 
 
Note: for the following questions (d) and (e), the writeup will require a specific rule ordering 
but the program need not sort the output. 
 
(d) [10pts] 
 
Identify pairs of items (X, Y) such that the support of {X, Y} is at least 100. For all such pairs, 
compute the confidence scores of the corresponding association rules: X ⇒ Y, Y ⇒ X. Sort the 
rules in decreasing order of confidence scores and list the top 5 rules in the writeup. Break ties, 
if any, by lexicographically increasing order on the left hand side of the rule. 
 
(e) [10pts] 
 
Identify item triples (X, Y, Z) such that the support of {X, Y, Z} is at least 100. For all such triples, 
compute the confidence scores of the corresponding association rules: (X, Y) ⇒ Z, (X, Z) ⇒ Y, 
and (Y, Z) ⇒ X. Sort the rules in decreasing order of confidence scores and list the top 5 rules in 
the writeup. Order the left-hand-side pair lexicographically and break ties, if any, by 
lexicographical order of the first then the second item in the pair. 
 
What to submit: 
 
Include your properly named code file (e.g., question_2.java or question_2.py), and include the 
answers to the following questions in your writeup: 
 (i) Explanation for 2(a). 
 
(ii) Proofs and/or counterexamples for 2(b). 
 
(iii) Explanation for 2(c). 
 
(iv) Top 5 rules with confidence scores for 2(d). 
 
(v) Top 5 rules with confidence scores for 2(e). 
 
3. Locality-Sensitive Hashing (30 pts) 
 
When simulating a random permutation of rows, as described in Sec 3.3.5 of MMDS textbook, 
we could save a lot of time if we restricted our attention to a randomly chosen k of the n rows, 
rather than hashing all the row numbers. The downside of doing so is that if none of the k rows 
contains a 1 in a certain column, then the result of the min-hashing is “don’t know,” i.e., we get 
no row number as a min-hash value. It would be a mistake to assume that two columns that 
both min-hash to “don’t know” are likely to be similar. However, if the probability of getting 
“don’t know” as a min-hash value is small, we can tolerate the situation, and simply ignore such 
min-hash values when computing the fraction of min-hashes in which two columns agree. 
 
(a) [10 pts] 
 
Suppose a column has m 1’s and therefore (n-m) 0’s. Prove that the probability we get 
“don’t know” as the min-hash value for this column is at most (
+,-
+ ).. 
 
(b) [10 pts] 
 
Suppose we want the probability of “don’t know” to be at most  ,/0. Assuming n and m are 
both very large (but n is much larger than m or k), give a simple approximation to the smallest 
value of k that will assure this probability is at most  ,/0. Hints: (1) You can use (
+,-
+ ). as the 
exact value of the probability of “don’t know.” (2) Remember that for large x, (1 − /
1
)1 ≈ 1/ . 
 
(c) [10 pts] 
 
Note: This question should be considered separate from the previous two parts, in that we are 
no longer restricting our attention to a randomly chosen subset of the rows. 
 When min-hashing, one might expect that we could estimate the Jaccard similarity without 
using all possible permutations of rows. For example, we could only allow cyclic permutations 
i.e., start at a randomly chosen row r, which becomes the first in the order, followed by rows 
r+1, r+2, and so on, down to the last row, and then continuing with the first row, second row, 
and so on, down to row r−1. There are only n such permutations if there are n rows. However, 
these permutations are not sufficient to estimate the Jaccard similarity correctly. 
 
Give an example of two columns such that the probability (over cyclic permutations only) that 
their min-hash values agree is not the same as their Jaccard similarity. In your answer, please 
provide (a) an example of a matrix with two columns (let the two columns correspond to sets 
denoted by S1 and S2) (b) the Jaccard similarity of S1 and S2, and (c) the probability that a 
random cyclic permutation yields the same min-hash value for both S1 and S2. 
 
What to submit: 
 
Include the following in your writeup: 
 
(i) Proof for 3(a) 
 
(ii) Derivation and final answer for 3(b) 
 
(iii) Example for 3(c) 
 
請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp




 

掃一掃在手機打開當前頁
  • 上一篇:FINM8006代寫、代做Python編程設計
  • 下一篇:&#160;ICT50220代做、代寫c++,Java程序設計
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
  • 短信驗證碼 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    超碰在线cao| 精品美女久久| 欧美亚洲综合视频| 欧美日韩四区| 欧美色图麻豆| 国产精品一区二区三区四区在线观看| www.精品| 视频一区二区三区入口| 99精品在线免费在线观看| 国产在视频线精品视频www666| 欧美一级免费| 日本一区二区在线看| 91成人精品视频| 美女视频免费精品| 日韩欧美中文在线观看| 欧美日韩一区二区国产| 国产乱子精品一区二区在线观看| 色男人天堂综合再现| 亚洲精品国产首次亮相| 台湾亚洲精品一区二区tv| 日本亚洲欧美天堂免费| 国产精品成人3p一区二区三区| 欧美日韩va| 色综合一本到久久亚洲91| 免费精品视频| 五月婷婷亚洲| 99久精品视频在线观看视频| avtt综合网| 日韩欧美黄色| 综合亚洲自拍| 国产精品**亚洲精品| 麻豆精品一区二区av白丝在线| 91福利精品在线观看| 男人最爱成人网| 三级电影一区| 蜜臀久久99精品久久久久宅男| 午夜国产精品视频| 婷婷成人在线| 激情综合自拍| 黑人操亚洲人| 羞羞答答成人影院www| 亚洲特级毛片| 久久网站免费观看| 999久久久免费精品国产| 久久久久国产精品一区二区| 国产图片一区| 美女一区二区在线观看| 精品久久ai电影| 999国产精品视频| 久久亚洲成人| 性欧美69xoxoxoxo| 99视频精品| 免费高清在线视频一区·| 免播放器亚洲一区| h片在线观看视频免费| 久久久久久一区二区| 色135综合网| 日韩毛片视频| jizz久久久久久| 美女精品一区二区| 综合天堂av久久久久久久| 亚洲自拍偷拍网| 国产精品一区二区99| 日本一道高清一区二区三区| 日韩欧美激情电影| 久久久久久久久久久9不雅视频| 亚洲福利久久| 男人的天堂亚洲在线| 97久久夜色精品国产| 涩涩av在线| 日韩国产欧美一区二区三区| 一区二区不卡| 视频精品二区| 999久久久精品国产| 99pao成人国产永久免费视频| 国产精品入口66mio| 日韩伦理精品| 日欧美一区二区| 日韩高清成人在线| 久久久久蜜桃| 视频在线观看一区| 精品国模一区二区三区| 日日摸夜夜添夜夜添精品视频| 国产精品成人3p一区二区三区| 三级欧美日韩| 亚洲精品电影| 国产成人精品亚洲日本在线观看| 免费亚洲视频| 久久伦理中文字幕| 久久精品亚洲人成影院 | 欧美大黑bbbbbbbbb在线| 视频在线观看一区| 国产亚洲人成a在线v网站 | 欧美精品中文| 久久亚洲风情| 亚洲国产国产亚洲一二三| 国产欧美日本| 极品av少妇一区二区| 玖玖在线播放| 国产精品啊啊啊| 国内视频在线精品| 免费xxxx性欧美18vr| 麻豆91在线播放| 国产精品一区二区三区美女| 国产精品人人爽人人做我的可爱| 精品日韩视频| 九九九九九九精品任你躁| 91成人看片| 日韩深夜福利网站| 久久视频免费| 免费看的黄色欧美网站| 国产日韩精品视频一区二区三区| 日韩高清一级| 国产亚洲激情| 日本sm残虐另类| 麻豆精品少妇| 日韩成人影院| 日本午夜精品久久久| 日韩午夜在线| 日本一区二区三区中文字幕| 日韩免费精品| 蜜桃久久久久久| 国产精品美女久久久久久不卡| 欧洲杯足球赛直播| 欧美成人毛片| 精品久久成人| 欧美三区四区| 91麻豆精品激情在线观看最新| 蜜桃视频在线观看一区二区| 成人国产精品一区二区网站| 1024日韩| 国产日韩一区| 欧美亚洲国产激情| 国产精品一二| 久久久久午夜电影| 日韩成人综合网| 久久精品青草| 九九热这里有精品| 91精品国产自产拍在线观看蜜 | 日本а中文在线天堂| 亚州av一区| 蜜臀91精品一区二区三区| 国产探花一区二区| 免费的国产精品| 日韩av中文字幕一区二区| 蜜臀a∨国产成人精品| 亚州精品视频| av在线私库| 国产精品极品国产中出| av在线一区不卡| 久久久精品日韩| 亚欧美中日韩视频| 亚洲精品二区三区| 国产不卡精品| 成入视频在线观看| 99精品国产一区二区三区2021| 日韩免费视频| 亚洲va在线| 欧美精品导航| 成人亚洲一区| 欧美激情影院| 日本网站在线观看一区二区三区| 亚洲欧美偷拍自拍| 国产精品2区| 亚洲欧洲自拍| 91精品国产调教在线观看| 日本成人在线视频网站| 欧美资源在线| 激情小说亚洲图片| 国内精品亚洲| 国产精品成人一区二区不卡| 亚洲一级大片| 麻豆一区二区三| 蜜臀精品一区二区三区在线观看| 大香伊人久久精品一区二区| 国产欧美日韩亚洲一区二区三区| 黄色av成人| 国产情侣一区在线| 久久一区精品| 激情国产在线| 国产精品99免费看| 亚洲精品亚洲人成在线| 青青久久精品| 美女国产一区| 久久精品综合| 最新亚洲精品| 肉丝袜脚交视频一区二区| 丝袜a∨在线一区二区三区不卡| 色妞ww精品视频7777| 日本午夜一本久久久综合| 97人人精品| 亚洲精品网址| 第九色区aⅴ天堂久久香| 午夜亚洲福利| 日韩中文视频| 石原莉奈在线亚洲二区| 香蕉人人精品| 9999久久久久| 99er精品视频| 日韩高清在线电影|